傻大方摘要：【源码|C源码ERA1nov11( 二 )|ERA1nov11】chessxy=tag; if(tag = X*Y)return 1; flag=nextxy(y1, count); while(flag=0 flag=nextxy(y1, count); while(flag)if(TravelChessBoard(x1, y1, tag+1) return 1; x1=x; y1=y; count=count+1; flag=nextxy(y1, coun...

chessxy=tag;
if(tag = X*Y)return 1;
flag=nextxy(&x1, &y1, count);
while(flag=0 & count7)count=count+1;
flag=nextxy(&x1 。

【源码|C源码ERA1nov11】16、, &y1, count);
while(flag)if(TravelChessBoard(x1, y1, tag+1) return 1;
x1=x;
y1=y;
count=count+1;
flag=nextxy(&x1, &y1, count);
/*寻找下一个(x,y)*/while(flag=0 & count7)/*循环地寻找下一个(x,y)*/count=count+1;
flag=nextxy(&x1, &y1, count);
if(flag = 0)chessxy=0;
return 0;
int main()int i, j;
for(i=0;
iX;
i+)for(j=0;
jY;
j+)chessij=0;
if(TravelChessBoard(2, 0, 1)for(i=0;
iX;
i+)for(j=0;
jY;
j+)printf(%-5d, chessij);
printf(n);
printf(The horse has travelled the chess boradn);
elseprintf(The horse cannot travel the chess boardn);
return 0;
6 。

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标题：源码|C源码ERA1nov11( 二 )