(?x)Input(x)?Unification(x)?(?y)output(y)?Fall(y)10解：所求CF(H)=0.864 ?x(?P(x)?yQ(x,y) 1）原式=11. 解（?x?y(?P(x)?Q(x,y) = ?x(?P(x)?xQ(x) （2）原式=?x(?P(x)?yQ(y) =?x?(?P(x)?yQ(y) =?x(P(x)?yQ(y) =?x(P(x)?y?Q(y) =?x?y(P(x)?Q(y) =12. 解： 。

【人工智能|人工智能测试题答案】33、 1) (x) P(x) (x) Q(x) (x) ( P(x) Q(x) )= (x) P(x) (x) Q(x) ) (y) ( P(y) Q(y) ) = (y) (x) (P(x) Q(x) P(y) Q(y) ) = (y) (x) ( (P(x) P(y) Q(y) ) (Q(x) P(y) Q(y) ) ) 化为skolem子句形： (P(x) P(a) Q(a) ) (Q(x) P(a) Q(a) ) 2) (x) ( P(x) (y) ( (z) Q(z , y) (z)R(y , z) ) ) = (x) (y) (z) (v) ( P(x) Q(z , y) R(y , v) 化为skolem子句形： P(x) Q(z , y) R(y , v) 3) (x) P(x) (x) ( (z) (Q(x ,z ) (y)R(x , y , z) ) = (x) ( P(x) (z)( Q(x ,z ) (y)R(x , y, z) ) = (x) (z) (y) (P(x) Q(x ,z ) R(x , y, z) ) 化为skolem子句形： P(a) Q(a ,z ) R(a , y, z) 更多课程资料请到大学课程网学习www.0206.cc 。

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标题：人工智能|人工智能测试题答案( 五 )